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11a^2+30a-9=0
a = 11; b = 30; c = -9;
Δ = b2-4ac
Δ = 302-4·11·(-9)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-36}{2*11}=\frac{-66}{22} =-3 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+36}{2*11}=\frac{6}{22} =3/11 $
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